MYSQL查找从小到大排列第90%个位置的数据

方法一（存储过程实现）：

begin
DECLARE cnt INT DEFAULT 0;
select count(*) into cnt from user;
set cnt = round(cnt*0.9)-1;
select * from user limit cnt, 1;
end

方法二（直接查询，，只有查询权限的时候可以考虑）：

这种方法也是解决mysql limit后面不支持变量的问题

SELECT COUNT(*) INTO @cnt FROM cmb_loading_count_20141013 WHERE ver>=1003002251;
SET @cnt = ROUND(@cnt*0.9)-1;
SET @stmt = ‘select loading_time from cmb_loading_count_20141013 where ver>=1003002251 order by loading_time asc limit ?,?‘;
prePARE s1 FROM @stmt;
SET @end = 1;
EXECUTE s1 USING @cnt,@end;
DEALLOCATE prePARE s1;

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